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Python deque 源码分析

·1173 words·6 mins

deque 是 Python 中的一个双端队列,deque 来源于 double-ended queue 的缩写,写作 deque 读作 deck。对于常见的数据结构 list 来说,下标为 0 的 pushpop 操作需要移动整个 list。而 deque 则不需要。并且它是线程安全的。除此之外还能为其设置 max-length,当 deque 满时,会自动丢弃相反一端的元素

deque 提供了如下的方法

['append', 'appendleft', 'clear', 'copy', 'count', 'extend', 'extendleft', 'index', 'insert', 'maxlen', 'pop', 'popleft', 'remove', 'reverse', 'rotate']

其源码位于 Modules/_collectionsmodule.c

先来看几个和 deque 相关结构体

#define BLOCKLEN 64
#define CENTER ((BLOCKLEN - 1) / 2)

typedef struct BLOCK {
    struct BLOCK *leftlink;
    PyObject *data[BLOCKLEN];
    struct BLOCK *rightlink;
} block;

block 类型含有指向左右两个 block 的指针,是一个链表结构的结点(node)。并且包含一个长度为 64 的指针数组,数组的每一个元素都是一个指向 PyObject 的指针

typedef struct {
    PyObject_VAR_HEAD
    block *leftblock;
    block *rightblock;
    Py_ssize_t leftindex;       /* 0 <= leftindex < BLOCKLEN */
    Py_ssize_t rightindex;      /* 0 <= rightindex < BLOCKLEN */
    size_t state;               /* incremented whenever the indices move */
    Py_ssize_t maxlen;
    PyObject *weakreflist;
} dequeobject;

dequeobject 类型的 leftblockrightblock 分别指向此 deque 的最左和最右的 blockleftindexrightindexleftblockrightblockdata 数组的索引,用于记录存储位置。maxlendeque 的最大长度

有了以上的准备,便可以来看看 deque 对象是如何生成的

static PyObject *
deque_new(PyTypeObject *type, PyObject *args, PyObject *kwds)
{
    dequeobject *deque;
    block *b;

    /* create dequeobject structure */
    deque = (dequeobject *)type->tp_alloc(type, 0);
    if (deque == NULL)
        return NULL;

    b = newblock(0);
    if (b == NULL) {
        Py_DECREF(deque);
        return NULL;
    }
    MARK_END(b->leftlink);
    MARK_END(b->rightlink);

    assert(BLOCKLEN >= 2);
    Py_SIZE(deque) = 0;
    deque->leftblock = b;
    deque->rightblock = b;
    deque->leftindex = CENTER + 1;
    deque->rightindex = CENTER;
    deque->state = 0;
    deque->maxlen = -1;
    deque->weakreflist = NULL;

    return (PyObject *)deque;
}

deque = (dequeobject *)type->tp_alloc(type, 0); 为分配 deque 的存储空间。tp_alloc 文档中有说明

newlbock(0) 为创建了一个 block

MARK_END 是一个 macro,用于将指针指向 NULL #define MARK_END(link) link = NULL;

第一次设置 deque->leftindex = CENTER + 1; deque->rightindex = CENTER; 是因为共享了一个 block

append 操作的源码如下

static PyObject *
deque_append(dequeobject *deque, PyObject *item)
{
    deque->state++;
    if (deque->rightindex == BLOCKLEN - 1) {
        block *b = newblock(Py_SIZE(deque));
        if (b == NULL)
            return NULL;
        b->leftlink = deque->rightblock;
        CHECK_END(deque->rightblock->rightlink);
        deque->rightblock->rightlink = b;
        deque->rightblock = b;
        MARK_END(b->rightlink);
        deque->rightindex = -1;
    }
    Py_INCREF(item);
    Py_SIZE(deque)++;
    deque->rightindex++;
    deque->rightblock->data[deque->rightindex] = item;
    deque_trim_left(deque);
    Py_RETURN_NONE;
}

这里首先会判断 dequerightindex 是否为 63。一个 block 最多持有 64 个 PyObject 的引用。如果达到上限则会创建一个新的 block

CHECK_END 也是一个 macro,用于在赋值时检查是否为 NULL

#define CHECK_END(link) assert(link == NULL);

Py_INCREF(item); 用于增加对象的引用计数。

trim_left 会检查 deque 的长度是否超过设置的最大长度。若超过则会将最左侧的元素 pop 出去。同理 trim_rightpop 最右侧的元素

deque_trim_left(dequeobject *deque)
{
    if (deque->maxlen != -1 && Py_SIZE(deque) > deque->maxlen) {
        PyObject *rv = deque_popleft(deque, NULL);
        assert(rv != NULL);
        assert(Py_SIZE(deque) <= deque->maxlen);
        Py_DECREF(rv);
    }
}

deque_appendleft 操作正相反,不再多说

deque_extend 源码如下

static PyObject *
deque_extend(dequeobject *deque, PyObject *iterable)
{
    PyObject *it, *item;

    /* Handle case where id(deque) == id(iterable) */
    if ((PyObject *)deque == iterable) {
        PyObject *result;
        PyObject *s = PySequence_List(iterable);
        if (s == NULL)
            return NULL;
        result = deque_extend(deque, s);
        Py_DECREF(s);
        return result;
    }

    /* Space saving heuristic.  Start filling from the left */
    if (Py_SIZE(deque) == 0) {
        assert(deque->leftblock == deque->rightblock);
        assert(deque->leftindex == deque->rightindex+1);
        deque->leftindex = 1;
        deque->rightindex = 0;
    }

    it = PyObject_GetIter(iterable);
    if (it == NULL)
        return NULL;

    if (deque->maxlen == 0)
        return consume_iterator(it);

    while ((item = PyIter_Next(it)) != NULL) {
        deque->state++;
        if (deque->rightindex == BLOCKLEN - 1) {
            block *b = newblock(Py_SIZE(deque));
            if (b == NULL) {
                Py_DECREF(item);
                Py_DECREF(it);
                return NULL;
            }
            b->leftlink = deque->rightblock;
            CHECK_END(deque->rightblock->rightlink);
            deque->rightblock->rightlink = b;
            deque->rightblock = b;
            MARK_END(b->rightlink);
            deque->rightindex = -1;
        }
        Py_SIZE(deque)++;
        deque->rightindex++;
        deque->rightblock->data[deque->rightindex] = item;
        deque_trim_left(deque);
    }
    if (PyErr_Occurred()) {
        Py_DECREF(it);
        return NULL;
    }
    Py_DECREF(it);
    Py_RETURN_NONE;
}

首先是为了防止循环引用

/* Handle case where id(deque) == id(iterable) */
if ((PyObject *)deque == iterable) {
    PyObject *result;
    PyObject *s = PySequence_List(iterable);
    if (s == NULL)
        return NULL;
    result = deque_extend(deque, s);
    Py_DECREF(s);
    return result;
}

然后就是一个优化,如果当前 deque 中无任何元素。会调整 leftindexrightindex 的位置。为即将实施的大量右侧插入腾出位置

if (Py_SIZE(deque) == 0) {
    assert(deque->leftblock == deque->rightblock);
    assert(deque->leftindex == deque->rightindex+1);
    deque->leftindex = 1;
    deque->rightindex = 0;                                                
}           

dequemaxlen 为 0 时,会直接将 iterator 迭代完

static PyObject*
consume_iterator(PyObject *it)
{
    PyObject *item;

    while ((item = PyIter_Next(it)) != NULL) {
        Py_DECREF(item);
    }
    Py_DECREF(it);
    if (PyErr_Occurred())
        return NULL;
    Py_RETURN_NONE;
}

之后便是和 append 相似的操作

pop 操作首先从 rightblock 中取出 rightindex 的元素。然后判断 block 的大小,决定是否需要 free。特别地,当 deque 中的元素数目为 0 时,会重置 leftindexrightindex 的值。源码如下

static PyObject *
deque_pop(dequeobject *deque, PyObject *unused)
{
    PyObject *item;
    block *prevblock;

    if (Py_SIZE(deque) == 0) {
        PyErr_SetString(PyExc_IndexError, "pop from an empty deque");
        return NULL;
    }
    item = deque->rightblock->data[deque->rightindex];
    deque->rightindex--;
    Py_SIZE(deque)--;
    deque->state++;

    if (deque->rightindex == -1) {
        if (Py_SIZE(deque)) {
            prevblock = deque->rightblock->leftlink;
            assert(deque->leftblock != deque->rightblock);
            freeblock(deque->rightblock);
            CHECK_NOT_END(prevblock);
            MARK_END(prevblock->rightlink);
            deque->rightblock = prevblock;
            deque->rightindex = BLOCKLEN - 1;
        } else {
            assert(deque->leftblock == deque->rightblock);
            assert(deque->leftindex == deque->rightindex+1);
            /* re-center instead of freeing a block */
            deque->leftindex = CENTER + 1;
            deque->rightindex = CENTER;
        }
    }
    return item;
}

rotate 方法不仅作为公共方法被使用,内部其他方法也有使用,比如 removerotate(1) 或者 rotate(-1) 是最常见的情况。所以任何的优化手段都不能使这两种情况的性能下降。概念上,一个 rotate 操作相当于一侧 pop 另一侧 append。然而 pop/append 会产生不必要的性能消耗,因为带来了引用计数上的增减(pop -1, append +1)。最好的方法是移动指针。当批量移动指针时,memcpy 是一个诱人的选择。但事实证明它比循环慢。原因有很多:memcpy 不能提前知道我们复制的是源和目标是指针对齐并且不重叠的指针而不是字节;移动一个指针是最常见的情况;从不需要移动超过 BLOCKLEN 指针。对于大规模的 rotatenewblockfreeblock 不会被调用超过一次。之前空的 block 会被重复使用,如果有一个 block 在最后被留下,才会释放。

static int
_deque_rotate(dequeobject *deque, Py_ssize_t n)
{
    block *b = NULL;
    block *leftblock = deque->leftblock;
    block *rightblock = deque->rightblock;
    Py_ssize_t leftindex = deque->leftindex;
    Py_ssize_t rightindex = deque->rightindex;
    Py_ssize_t len=Py_SIZE(deque), halflen=len>>1;
    int rv = -1;

    // 当 deque 长度为 0 或 1 时,rotate 是无意义的,直接返回
    if (len <= 1)
        return 0;
    // 优化 减少移动次数
    // halflen 为 len 的一半 9>>1==4
    // 当 rotate(8) 相当于 rotate(-1)
    if (n > halflen || n < -halflen) {
        n %= len;
        if (n > halflen)
            n -= len;
        else if (n < -halflen)
            n += len;
    }
    assert(len > 1);
    assert(-halflen <= n && n <= halflen);

    deque->state++;
    while (n > 0) {
        // 左侧 block 已满,开辟新存储空间
        if (leftindex == 0) {
            if (b == NULL) {
                b = newblock(len);
                if (b == NULL)
                    goto done;
            }
            b->rightlink = leftblock;
            CHECK_END(leftblock->leftlink);
            leftblock->leftlink = b;
            leftblock = b;
            MARK_END(b->leftlink);
            leftindex = BLOCKLEN;
            // *
            b = NULL;
        }
        assert(leftindex > 0);
        {
            PyObject **src, **dest;
            Py_ssize_t m = n;

            // 要移动多个 block 的情况,先移动一个
            if (m > rightindex + 1)
                m = rightindex + 1;
            if (m > leftindex)
                m = leftindex;
            assert (m > 0 && m <= len);
            rightindex -= m;
            leftindex -= m;
            src = &rightblock->data[rightindex + 1];
            dest = &leftblock->data[leftindex];
            // 计算剩余需要移动的量
            n -= m;
            do {
                *(dest++) = *(src++);
            } while (--m);
        }
        // rightblock 为空
        if (rightindex == -1) {
            // 这里没有 free 已经为空的 rightblock
            assert(leftblock != rightblock);
            assert(b == NULL);
            // 复用,若 leftblock 满会直接用这块空间
            b = rightblock;
            CHECK_NOT_END(rightblock->leftlink);
            rightblock = rightblock->leftlink;
            MARK_END(rightblock->rightlink);
            rightindex = BLOCKLEN - 1;
        }
    }
    while (n < 0) {
        // omit
    }
    rv = 0;
done:
    if (b != NULL)
        freeblock(b);
    deque->leftblock = leftblock;
    deque->rightblock = rightblock;
    deque->leftindex = leftindex;
    deque->rightindex = rightindex;

    return rv;
}

remove 操作借助了 rotate

static PyObject *
deque_remove(dequeobject *deque, PyObject *value)
{
    Py_ssize_t i, n=Py_SIZE(deque);

    for (i=0 ; i<n ; i++) {
        PyObject *item = deque->leftblock->data[deque->leftindex];
        int cmp = PyObject_RichCompareBool(item, value, Py_EQ);

        if (Py_SIZE(deque) != n) {
            PyErr_SetString(PyExc_IndexError,
                "deque mutated during remove().");
            return NULL;
        }
        // 找到此元素
        if (cmp > 0) {
            PyObject *tgt = deque_popleft(deque, NULL);
            assert (tgt != NULL);
            if (_deque_rotate(deque, i))
                return NULL;
            Py_DECREF(tgt);
            Py_RETURN_NONE;
        }
        // error
        else if (cmp < 0) {
            _deque_rotate(deque, i);
            return NULL;
        }
        // 未找到 rotate(-1)
        _deque_rotate(deque, -1);
    }
    PyErr_SetString(PyExc_ValueError, "deque.remove(x): x not in deque");
    return NULL;
}

例如 remove(3)

i=0       [1, 2, 3, 4, 5]
i=1       [2, 3, 4, 5, 1]
i=2       [3, 4, 5, 1, 2]
popleft   [4, 5, 1, 2]
rotate(i) [1, 2, 4, 5]

关于 PyObject_RichCompareBool,文档中有说明

deque_reverse 就是简单的 swap 了 len/2
deque_count 也是在简单的循环计数
剩下的几个方便便不再赘述了